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18x=4x^2
We move all terms to the left:
18x-(4x^2)=0
determiningTheFunctionDomain -4x^2+18x=0
a = -4; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-4)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-4}=\frac{-36}{-8} =4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-4}=\frac{0}{-8} =0 $
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